Port Jefferson, OH Profile
Port Jefferson, OH, population 322, is located
in Ohio's Shelby county,
about 39.7 miles from Dayton and 63.3 miles from Columbus.
Through the 90's Port Jefferson's population has declined by about 16%.
It is estimated that in the first 5 years of the past decade the population of Port Jefferson has grown by about 2%. Since 2005 Port Jefferson's population has declined by about 3%.
Population Statistics
Gender
| Population by Gender |
| Males | 51% |
| Females | 49% |
Race
| Population by Race |
| White | 100% |
| African American | 0% |
| Native American | 0% |
| Asian | 0% |
| Hawaiian | 0% |
| Other/Mixed | 0% |
Age
| Median Age |
| Population | 9.99 |
| Males | 9.99 |
| Females | 9.99 |
| Males by Age | Females by Age |
| Under 20 | 9.99% | | Under 20: | 9.99% |
| 20 to 40 | 9.99% | | 20 to 40: | 9.99% |
| 40 to 60 | 9.99% | | 40 to 60: | 9.99% |
| Over 60 | 7.00% | | Over 60: | 9.99% |
Size
| Population by Year | Change Rate |
| 2000 | 333 | N/A |
| 2001 | 335 | 0.60% |
| 2002 | 334 | -0.30% |
| 2003 | 333 | -0.30% |
| 2004 | 332 | -0.30% |
| 2005 | 332 | 0.00% |
| 2006 | 327 | -1.51% |
| 2007 | 325 | -0.61% |
| 2008 | 323 | -0.62% |
| 2009 | 322 | -0.31% |
Economics
| Household Income |
| Median | $34,306 |
Location
| Elevation | 974 feet above sea level |
| Land Area | 0.2 Square Miles |